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3(2x-4)=4(3x+5)
We move all terms to the left:
3(2x-4)-(4(3x+5))=0
We multiply parentheses
6x-(4(3x+5))-12=0
We calculate terms in parentheses: -(4(3x+5)), so:We get rid of parentheses
4(3x+5)
We multiply parentheses
12x+20
Back to the equation:
-(12x+20)
6x-12x-20-12=0
We add all the numbers together, and all the variables
-6x-32=0
We move all terms containing x to the left, all other terms to the right
-6x=32
x=32/-6
x=-5+1/3
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