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3(2x-4)=4(x+5)
We move all terms to the left:
3(2x-4)-(4(x+5))=0
We multiply parentheses
6x-(4(x+5))-12=0
We calculate terms in parentheses: -(4(x+5)), so:We get rid of parentheses
4(x+5)
We multiply parentheses
4x+20
Back to the equation:
-(4x+20)
6x-4x-20-12=0
We add all the numbers together, and all the variables
2x-32=0
We move all terms containing x to the left, all other terms to the right
2x=32
x=32/2
x=16
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