3(2x-4)=5(z+2)

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Solution for 3(2x-4)=5(z+2) equation:


Simplifying
3(2x + -4) = 5(z + 2)

Reorder the terms:
3(-4 + 2x) = 5(z + 2)
(-4 * 3 + 2x * 3) = 5(z + 2)
(-12 + 6x) = 5(z + 2)

Reorder the terms:
-12 + 6x = 5(2 + z)
-12 + 6x = (2 * 5 + z * 5)
-12 + 6x = (10 + 5z)

Solving
-12 + 6x = 10 + 5z

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 6x = 10 + 12 + 5z

Combine like terms: -12 + 12 = 0
0 + 6x = 10 + 12 + 5z
6x = 10 + 12 + 5z

Combine like terms: 10 + 12 = 22
6x = 22 + 5z

Divide each side by '6'.
x = 3.666666667 + 0.8333333333z

Simplifying
x = 3.666666667 + 0.8333333333z

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