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3(2x-4)=6(x-2)+4
We move all terms to the left:
3(2x-4)-(6(x-2)+4)=0
We multiply parentheses
6x-(6(x-2)+4)-12=0
We calculate terms in parentheses: -(6(x-2)+4), so:We get rid of parentheses
6(x-2)+4
We multiply parentheses
6x-12+4
We add all the numbers together, and all the variables
6x-8
Back to the equation:
-(6x-8)
6x-6x+8-12=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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