3(2x-4)=7+(x+5)

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Solution for 3(2x-4)=7+(x+5) equation: 



3(2x-4)=7+(x+5)

We move all terms to the left:

3(2x-4)-(7+(x+5))=0

We multiply parentheses

6x-(7+(x+5))-12=0



We calculate terms in parentheses: -(7+(x+5)), so:

7+(x+5)

determiningTheFunctionDomain
(x+5)+7

We get rid of parentheses

x+5+7

We add all the numbers together, and all the variables

x+12

Back to the equation:

-(x+12)



We get rid of parentheses

6x-x-12-12=0

We add all the numbers together, and all the variables

5x-24=0

We move all terms containing x to the left, all other terms to the right

5x=24

x=24/5

x=4+4/5

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