3(2x-4x)=9+3x(4x+2)

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Solution for 3(2x-4x)=9+3x(4x+2) equation: 



3(2x-4x)=9+3x(4x+2)

We move all terms to the left:

3(2x-4x)-(9+3x(4x+2))=0

We add all the numbers together, and all the variables

3(-2x)-(9+3x(4x+2))=0

We multiply parentheses

-6x-(9+3x(4x+2))=0



We calculate terms in parentheses: -(9+3x(4x+2)), so:

9+3x(4x+2)

determiningTheFunctionDomain
3x(4x+2)+9

We multiply parentheses

12x^2+6x+9

Back to the equation:

-(12x^2+6x+9)



We get rid of parentheses

-12x^2-6x-6x-9=0

We add all the numbers together, and all the variables

-12x^2-12x-9=0

a = -12; b = -12; c = -9;
Δ = b2-4ac
Δ = -122-4·(-12)·(-9)
Δ = -288
Delta is less than zero, so there is no solution for the equation

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