3(2x-5)+10=-(x+3)+12

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Solution for 3(2x-5)+10=-(x+3)+12 equation: 



3(2x-5)+10=-(x+3)+12

We move all terms to the left:

3(2x-5)+10-(-(x+3)+12)=0

We multiply parentheses

6x-(-(x+3)+12)-15+10=0



We calculate terms in parentheses: -(-(x+3)+12), so:

-(x+3)+12

We get rid of parentheses

-x-3+12

We add all the numbers together, and all the variables

-1x+9

Back to the equation:

-(-1x+9)



We add all the numbers together, and all the variables

6x-(-1x+9)-5=0

We get rid of parentheses

6x+1x-9-5=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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