3(2x-5)+13=2(x+4)+7

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Solution for 3(2x-5)+13=2(x+4)+7 equation:



3(2x-5)+13=2(x+4)+7
We move all terms to the left:
3(2x-5)+13-(2(x+4)+7)=0
We multiply parentheses
6x-(2(x+4)+7)-15+13=0
We calculate terms in parentheses: -(2(x+4)+7), so:
2(x+4)+7
We multiply parentheses
2x+8+7
We add all the numbers together, and all the variables
2x+15
Back to the equation:
-(2x+15)
We add all the numbers together, and all the variables
6x-(2x+15)-2=0
We get rid of parentheses
6x-2x-15-2=0
We add all the numbers together, and all the variables
4x-17=0
We move all terms containing x to the left, all other terms to the right
4x=17
x=17/4
x=4+1/4

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