3(2x-5)+13=4(x+1)

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Solution for 3(2x-5)+13=4(x+1) equation:



3(2x-5)+13=4(x+1)
We move all terms to the left:
3(2x-5)+13-(4(x+1))=0
We multiply parentheses
6x-(4(x+1))-15+13=0
We calculate terms in parentheses: -(4(x+1)), so:
4(x+1)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
We add all the numbers together, and all the variables
6x-(4x+4)-2=0
We get rid of parentheses
6x-4x-4-2=0
We add all the numbers together, and all the variables
2x-6=0
We move all terms containing x to the left, all other terms to the right
2x=6
x=6/2
x=3

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