3(2x-5)+1=7x-2(x+2)

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Solution for 3(2x-5)+1=7x-2(x+2) equation: 



3(2x-5)+1=7x-2(x+2)

We move all terms to the left:

3(2x-5)+1-(7x-2(x+2))=0

We multiply parentheses

6x-(7x-2(x+2))-15+1=0



We calculate terms in parentheses: -(7x-2(x+2)), so:

7x-2(x+2)

We multiply parentheses

7x-2x-4

We add all the numbers together, and all the variables

5x-4

Back to the equation:

-(5x-4)



We add all the numbers together, and all the variables

6x-(5x-4)-14=0

We get rid of parentheses

6x-5x+4-14=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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