3(2x-5)+20=5(2x-5)

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Solution for 3(2x-5)+20=5(2x-5) equation: 



3(2x-5)+20=5(2x-5)

We move all terms to the left:

3(2x-5)+20-(5(2x-5))=0

We multiply parentheses

6x-(5(2x-5))-15+20=0



We calculate terms in parentheses: -(5(2x-5)), so:

5(2x-5)

We multiply parentheses

10x-25

Back to the equation:

-(10x-25)



We add all the numbers together, and all the variables

6x-(10x-25)+5=0

We get rid of parentheses

6x-10x+25+5=0

We add all the numbers together, and all the variables

-4x+30=0

We move all terms containing x to the left, all other terms to the right

-4x=-30

x=-30/-4

x=7+1/2

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