3(2x-5)+2x=3(x-14)-33

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Solution for 3(2x-5)+2x=3(x-14)-33 equation: 



3(2x-5)+2x=3(x-14)-33

We move all terms to the left:

3(2x-5)+2x-(3(x-14)-33)=0

We add all the numbers together, and all the variables

2x+3(2x-5)-(3(x-14)-33)=0

We multiply parentheses

2x+6x-(3(x-14)-33)-15=0



We calculate terms in parentheses: -(3(x-14)-33), so:

3(x-14)-33

We multiply parentheses

3x-42-33

We add all the numbers together, and all the variables

3x-75

Back to the equation:

-(3x-75)



We add all the numbers together, and all the variables

8x-(3x-75)-15=0

We get rid of parentheses

8x-3x+75-15=0

We add all the numbers together, and all the variables

5x+60=0

We move all terms containing x to the left, all other terms to the right

5x=-60

x=-60/5

x=-12

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