3(2x-5)+49=-8(x-6)+18x-18

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Solution for 3(2x-5)+49=-8(x-6)+18x-18 equation:



3(2x-5)+49=-8(x-6)+18x-18
We move all terms to the left:
3(2x-5)+49-(-8(x-6)+18x-18)=0
We multiply parentheses
6x-(-8(x-6)+18x-18)-15+49=0
We calculate terms in parentheses: -(-8(x-6)+18x-18), so:
-8(x-6)+18x-18
We add all the numbers together, and all the variables
18x-8(x-6)-18
We multiply parentheses
18x-8x+48-18
We add all the numbers together, and all the variables
10x+30
Back to the equation:
-(10x+30)
We add all the numbers together, and all the variables
6x-(10x+30)+34=0
We get rid of parentheses
6x-10x-30+34=0
We add all the numbers together, and all the variables
-4x+4=0
We move all terms containing x to the left, all other terms to the right
-4x=-4
x=-4/-4
x=1

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