3(2x-5)+49=-8(x-6)+18x-18

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Solution for 3(2x-5)+49=-8(x-6)+18x-18 equation: 



3(2x-5)+49=-8(x-6)+18x-18

We move all terms to the left:

3(2x-5)+49-(-8(x-6)+18x-18)=0

We multiply parentheses

6x-(-8(x-6)+18x-18)-15+49=0



We calculate terms in parentheses: -(-8(x-6)+18x-18), so:

-8(x-6)+18x-18

We add all the numbers together, and all the variables

18x-8(x-6)-18

We multiply parentheses

18x-8x+48-18

We add all the numbers together, and all the variables

10x+30

Back to the equation:

-(10x+30)



We add all the numbers together, and all the variables

6x-(10x+30)+34=0

We get rid of parentheses

6x-10x-30+34=0

We add all the numbers together, and all the variables

-4x+4=0

We move all terms containing x to the left, all other terms to the right

-4x=-4

x=-4/-4

x=1

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