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3(2x-5)+4x=4(3x+2)-2x
We move all terms to the left:
3(2x-5)+4x-(4(3x+2)-2x)=0
We add all the numbers together, and all the variables
4x+3(2x-5)-(4(3x+2)-2x)=0
We multiply parentheses
4x+6x-(4(3x+2)-2x)-15=0
We calculate terms in parentheses: -(4(3x+2)-2x), so:We add all the numbers together, and all the variables
4(3x+2)-2x
We add all the numbers together, and all the variables
-2x+4(3x+2)
We multiply parentheses
-2x+12x+8
We add all the numbers together, and all the variables
10x+8
Back to the equation:
-(10x+8)
10x-(10x+8)-15=0
We get rid of parentheses
10x-10x-8-15=0
We add all the numbers together, and all the variables
-23!=0
There is no solution for this equation
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