3(2x-5)+4x=4-4(5x+1)

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Solution for 3(2x-5)+4x=4-4(5x+1) equation: 



3(2x-5)+4x=4-4(5x+1)

We move all terms to the left:

3(2x-5)+4x-(4-4(5x+1))=0

We add all the numbers together, and all the variables

4x+3(2x-5)-(4-4(5x+1))=0

We multiply parentheses

4x+6x-(4-4(5x+1))-15=0



We calculate terms in parentheses: -(4-4(5x+1)), so:

4-4(5x+1)

determiningTheFunctionDomain
-4(5x+1)+4

We multiply parentheses

-20x-4+4

We add all the numbers together, and all the variables

-20x

Back to the equation:

-(-20x)



We add all the numbers together, and all the variables

10x-(-20x)-15=0

We get rid of parentheses

10x+20x-15=0

We add all the numbers together, and all the variables

30x-15=0

We move all terms containing x to the left, all other terms to the right

30x=15

x=15/30

x=1/2

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