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3(2x-5)+6=4-5(x-7)
We move all terms to the left:
3(2x-5)+6-(4-5(x-7))=0
We multiply parentheses
6x-(4-5(x-7))-15+6=0
We calculate terms in parentheses: -(4-5(x-7)), so:We add all the numbers together, and all the variables
4-5(x-7)
determiningTheFunctionDomain -5(x-7)+4
We multiply parentheses
-5x+35+4
We add all the numbers together, and all the variables
-5x+39
Back to the equation:
-(-5x+39)
6x-(-5x+39)-9=0
We get rid of parentheses
6x+5x-39-9=0
We add all the numbers together, and all the variables
11x-48=0
We move all terms containing x to the left, all other terms to the right
11x=48
x=48/11
x=4+4/11
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