3(2x-5)+6=9x-42

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Solution for 3(2x-5)+6=9x-42 equation: 



3(2x-5)+6=9x-42

We move all terms to the left:

3(2x-5)+6-(9x-42)=0

We multiply parentheses

6x-(9x-42)-15+6=0

We get rid of parentheses

6x-9x+42-15+6=0

We add all the numbers together, and all the variables

-3x+33=0

We move all terms containing x to the left, all other terms to the right

-3x=-33

x=-33/-3

x=+11

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