3(2x-5)+7(5x-3)-8(4x-7)+5(12-10x)=48x-24

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Solution for 3(2x-5)+7(5x-3)-8(4x-7)+5(12-10x)=48x-24 equation:



3(2x-5)+7(5x-3)-8(4x-7)+5(12-10x)=48x-24
We move all terms to the left:
3(2x-5)+7(5x-3)-8(4x-7)+5(12-10x)-(48x-24)=0
We add all the numbers together, and all the variables
3(2x-5)+7(5x-3)-8(4x-7)+5(-10x+12)-(48x-24)=0
We multiply parentheses
6x+35x-32x-50x-(48x-24)-15-21+56+60=0
We get rid of parentheses
6x+35x-32x-50x-48x+24-15-21+56+60=0
We add all the numbers together, and all the variables
-89x+104=0
We move all terms containing x to the left, all other terms to the right
-89x=-104
x=-104/-89
x=1+15/89

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