3(2x-5)-16+5x=-8(3x-1)+2x+9

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Solution for 3(2x-5)-16+5x=-8(3x-1)+2x+9 equation:



3(2x-5)-16+5x=-8(3x-1)+2x+9
We move all terms to the left:
3(2x-5)-16+5x-(-8(3x-1)+2x+9)=0
We add all the numbers together, and all the variables
5x+3(2x-5)-(-8(3x-1)+2x+9)-16=0
We multiply parentheses
5x+6x-(-8(3x-1)+2x+9)-15-16=0
We calculate terms in parentheses: -(-8(3x-1)+2x+9), so:
-8(3x-1)+2x+9
We add all the numbers together, and all the variables
2x-8(3x-1)+9
We multiply parentheses
2x-24x+8+9
We add all the numbers together, and all the variables
-22x+17
Back to the equation:
-(-22x+17)
We add all the numbers together, and all the variables
11x-(-22x+17)-31=0
We get rid of parentheses
11x+22x-17-31=0
We add all the numbers together, and all the variables
33x-48=0
We move all terms containing x to the left, all other terms to the right
33x=48
x=48/33
x=1+5/11

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