3(2x-5)-3=3(x-3)+6

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Solution for 3(2x-5)-3=3(x-3)+6 equation: 



3(2x-5)-3=3(x-3)+6

We move all terms to the left:

3(2x-5)-3-(3(x-3)+6)=0

We multiply parentheses

6x-(3(x-3)+6)-15-3=0



We calculate terms in parentheses: -(3(x-3)+6), so:

3(x-3)+6

We multiply parentheses

3x-9+6

We add all the numbers together, and all the variables

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

6x-(3x-3)-18=0

We get rid of parentheses

6x-3x+3-18=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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