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3(2x-5)-3x=2(x-7)+1
We move all terms to the left:
3(2x-5)-3x-(2(x-7)+1)=0
We add all the numbers together, and all the variables
-3x+3(2x-5)-(2(x-7)+1)=0
We multiply parentheses
-3x+6x-(2(x-7)+1)-15=0
We calculate terms in parentheses: -(2(x-7)+1), so:We add all the numbers together, and all the variables
2(x-7)+1
We multiply parentheses
2x-14+1
We add all the numbers together, and all the variables
2x-13
Back to the equation:
-(2x-13)
3x-(2x-13)-15=0
We get rid of parentheses
3x-2x+13-15=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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