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3(2x-5)-4(x+1)=5(x+2)-2(2x+3)
We move all terms to the left:
3(2x-5)-4(x+1)-(5(x+2)-2(2x+3))=0
We multiply parentheses
6x-4x-(5(x+2)-2(2x+3))-15-4=0
We calculate terms in parentheses: -(5(x+2)-2(2x+3)), so:We add all the numbers together, and all the variables
5(x+2)-2(2x+3)
We multiply parentheses
5x-4x+10-6
We add all the numbers together, and all the variables
x+4
Back to the equation:
-(x+4)
2x-(x+4)-19=0
We get rid of parentheses
2x-x-4-19=0
We add all the numbers together, and all the variables
x-23=0
We move all terms containing x to the left, all other terms to the right
x=23
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