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3(2x-5)=(5x+7)
We move all terms to the left:
3(2x-5)-((5x+7))=0
We multiply parentheses
6x-((5x+7))-15=0
We calculate terms in parentheses: -((5x+7)), so:We get rid of parentheses
(5x+7)
We get rid of parentheses
5x+7
Back to the equation:
-(5x+7)
6x-5x-7-15=0
We add all the numbers together, and all the variables
x-22=0
We move all terms containing x to the left, all other terms to the right
x=22
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