3(2x-5)=-2(x+1)-4

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Solution for 3(2x-5)=-2(x+1)-4 equation: 



3(2x-5)=-2(x+1)-4

We move all terms to the left:

3(2x-5)-(-2(x+1)-4)=0

We multiply parentheses

6x-(-2(x+1)-4)-15=0



We calculate terms in parentheses: -(-2(x+1)-4), so:

-2(x+1)-4

We multiply parentheses

-2x-2-4

We add all the numbers together, and all the variables

-2x-6

Back to the equation:

-(-2x-6)



We get rid of parentheses

6x+2x+6-15=0

We add all the numbers together, and all the variables

8x-9=0

We move all terms containing x to the left, all other terms to the right

8x=9

x=9/8

x=1+1/8

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