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3(2x-5)=-4x+5(2x+1)
We move all terms to the left:
3(2x-5)-(-4x+5(2x+1))=0
We multiply parentheses
6x-(-4x+5(2x+1))-15=0
We calculate terms in parentheses: -(-4x+5(2x+1)), so:We get rid of parentheses
-4x+5(2x+1)
We multiply parentheses
-4x+10x+5
We add all the numbers together, and all the variables
6x+5
Back to the equation:
-(6x+5)
6x-6x-5-15=0
We add all the numbers together, and all the variables
-20!=0
There is no solution for this equation
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