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3(2x-5)=10x-4(x-1)
We move all terms to the left:
3(2x-5)-(10x-4(x-1))=0
We multiply parentheses
6x-(10x-4(x-1))-15=0
We calculate terms in parentheses: -(10x-4(x-1)), so:We get rid of parentheses
10x-4(x-1)
We multiply parentheses
10x-4x+4
We add all the numbers together, and all the variables
6x+4
Back to the equation:
-(6x+4)
6x-6x-4-15=0
We add all the numbers together, and all the variables
-19!=0
There is no solution for this equation
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