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3(2x-5)=2(2x+3)
We move all terms to the left:
3(2x-5)-(2(2x+3))=0
We multiply parentheses
6x-(2(2x+3))-15=0
We calculate terms in parentheses: -(2(2x+3)), so:We get rid of parentheses
2(2x+3)
We multiply parentheses
4x+6
Back to the equation:
-(4x+6)
6x-4x-6-15=0
We add all the numbers together, and all the variables
2x-21=0
We move all terms containing x to the left, all other terms to the right
2x=21
x=21/2
x=10+1/2
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