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3(2x-5)=3(10-x)
We move all terms to the left:
3(2x-5)-(3(10-x))=0
We add all the numbers together, and all the variables
3(2x-5)-(3(-1x+10))=0
We multiply parentheses
6x-(3(-1x+10))-15=0
We calculate terms in parentheses: -(3(-1x+10)), so:We get rid of parentheses
3(-1x+10)
We multiply parentheses
-3x+30
Back to the equation:
-(-3x+30)
6x+3x-30-15=0
We add all the numbers together, and all the variables
9x-45=0
We move all terms containing x to the left, all other terms to the right
9x=45
x=45/9
x=5
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