3(2x-5)=3(x-3)+12

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Solution for 3(2x-5)=3(x-3)+12 equation: 



3(2x-5)=3(x-3)+12

We move all terms to the left:

3(2x-5)-(3(x-3)+12)=0

We multiply parentheses

6x-(3(x-3)+12)-15=0



We calculate terms in parentheses: -(3(x-3)+12), so:

3(x-3)+12

We multiply parentheses

3x-9+12

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

6x-3x-3-15=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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