3(2x-5)=4(4x+7)+15

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Solution for 3(2x-5)=4(4x+7)+15 equation: 



3(2x-5)=4(4x+7)+15

We move all terms to the left:

3(2x-5)-(4(4x+7)+15)=0

We multiply parentheses

6x-(4(4x+7)+15)-15=0



We calculate terms in parentheses: -(4(4x+7)+15), so:

4(4x+7)+15

We multiply parentheses

16x+28+15

We add all the numbers together, and all the variables

16x+43

Back to the equation:

-(16x+43)



We get rid of parentheses

6x-16x-43-15=0

We add all the numbers together, and all the variables

-10x-58=0

We move all terms containing x to the left, all other terms to the right

-10x=58

x=58/-10

x=-5+4/5

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