3(2x-5)=4(4x+7)-15

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Solution for 3(2x-5)=4(4x+7)-15 equation: 



3(2x-5)=4(4x+7)-15

We move all terms to the left:

3(2x-5)-(4(4x+7)-15)=0

We multiply parentheses

6x-(4(4x+7)-15)-15=0



We calculate terms in parentheses: -(4(4x+7)-15), so:

4(4x+7)-15

We multiply parentheses

16x+28-15

We add all the numbers together, and all the variables

16x+13

Back to the equation:

-(16x+13)



We get rid of parentheses

6x-16x-13-15=0

We add all the numbers together, and all the variables

-10x-28=0

We move all terms containing x to the left, all other terms to the right

-10x=28

x=28/-10

x=-2+4/5

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