3(2x-5)=4(x+3)=

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Solution for 3(2x-5)=4(x+3)= equation: 



3(2x-5)=4(x+3)=

We move all terms to the left:

3(2x-5)-(4(x+3))=0

We multiply parentheses

6x-(4(x+3))-15=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

6x-4x-12-15=0

We add all the numbers together, and all the variables

2x-27=0

We move all terms containing x to the left, all other terms to the right

2x=27

x=27/2

x=13+1/2

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