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3(2x-5)=4x-(x+3)
We move all terms to the left:
3(2x-5)-(4x-(x+3))=0
We multiply parentheses
6x-(4x-(x+3))-15=0
We calculate terms in parentheses: -(4x-(x+3)), so:We get rid of parentheses
4x-(x+3)
We get rid of parentheses
4x-x-3
We add all the numbers together, and all the variables
3x-3
Back to the equation:
-(3x-3)
6x-3x+3-15=0
We add all the numbers together, and all the variables
3x-12=0
We move all terms containing x to the left, all other terms to the right
3x=12
x=12/3
x=4
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