3(2x-5)=5(x-4)+x+5

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Solution for 3(2x-5)=5(x-4)+x+5 equation:


Simplifying
3(2x + -5) = 5(x + -4) + x + 5

Reorder the terms:
3(-5 + 2x) = 5(x + -4) + x + 5
(-5 * 3 + 2x * 3) = 5(x + -4) + x + 5
(-15 + 6x) = 5(x + -4) + x + 5

Reorder the terms:
-15 + 6x = 5(-4 + x) + x + 5
-15 + 6x = (-4 * 5 + x * 5) + x + 5
-15 + 6x = (-20 + 5x) + x + 5

Reorder the terms:
-15 + 6x = -20 + 5 + 5x + x

Combine like terms: -20 + 5 = -15
-15 + 6x = -15 + 5x + x

Combine like terms: 5x + x = 6x
-15 + 6x = -15 + 6x

Add '15' to each side of the equation.
-15 + 15 + 6x = -15 + 15 + 6x

Combine like terms: -15 + 15 = 0
0 + 6x = -15 + 15 + 6x
6x = -15 + 15 + 6x

Combine like terms: -15 + 15 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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