3(2x-5)=7(x+3)

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Solution for 3(2x-5)=7(x+3) equation: 



3(2x-5)=7(x+3)

We move all terms to the left:

3(2x-5)-(7(x+3))=0

We multiply parentheses

6x-(7(x+3))-15=0



We calculate terms in parentheses: -(7(x+3)), so:

7(x+3)

We multiply parentheses

7x+21

Back to the equation:

-(7x+21)



We get rid of parentheses

6x-7x-21-15=0

We add all the numbers together, and all the variables

-1x-36=0

We move all terms containing x to the left, all other terms to the right

-x=36

x=36/-1

x=-36

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