3(2x-5)=8(x-2)

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Solution for 3(2x-5)=8(x-2) equation: 



3(2x-5)=8(x-2)

We move all terms to the left:

3(2x-5)-(8(x-2))=0

We multiply parentheses

6x-(8(x-2))-15=0



We calculate terms in parentheses: -(8(x-2)), so:

8(x-2)

We multiply parentheses

8x-16

Back to the equation:

-(8x-16)



We get rid of parentheses

6x-8x+16-15=0

We add all the numbers together, and all the variables

-2x+1=0

We move all terms containing x to the left, all other terms to the right

-2x=-1

x=-1/-2

x=1/2

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