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3(2x-5)=9(10x)
We move all terms to the left:
3(2x-5)-(9(10x))=0
determiningTheFunctionDomain 3(2x-5)-910x=0
We add all the numbers together, and all the variables
-910x+3(2x-5)=0
We multiply parentheses
-910x+6x-15=0
We add all the numbers together, and all the variables
-904x-15=0
We move all terms containing x to the left, all other terms to the right
-904x=15
x=15/-904
x=-15/904
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