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3(2x-5)=9-x/3
We move all terms to the left:
3(2x-5)-(9-x/3)=0
We add all the numbers together, and all the variables
3(2x-5)-(-x/3+9)=0
We multiply parentheses
6x-(-x/3+9)-15=0
We get rid of parentheses
6x+x/3-9-15=0
We multiply all the terms by the denominator
6x*3+x-9*3-15*3=0
We add all the numbers together, and all the variables
x+6x*3-72=0
Wy multiply elements
x+18x-72=0
We add all the numbers together, and all the variables
19x-72=0
We move all terms containing x to the left, all other terms to the right
19x=72
x=72/19
x=3+15/19
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