3(2x-5)=x(3x-1)

Solution for 3(2x-5)=x(3x-1) equation:

3(2x-5)=x(3x-1)

We move all terms to the left:

3(2x-5)-(x(3x-1))=0

We multiply parentheses

6x-(x(3x-1))-15=0


We calculate terms in parentheses: -(x(3x-1)), so:

x(3x-1)

We multiply parentheses

3x^2-1x

Back to the equation:

-(3x^2-1x)


We get rid of parentheses

-3x^2+6x+1x-15=0

We add all the numbers together, and all the variables

-3x^2+7x-15=0

a = -3; b = 7; c = -15;
Δ = b2-4ac
Δ = 72-4·(-3)·(-15)
Δ = -131
Delta is less than zero, so there is no solution for the equation