3(2x-5)=x(x+1)

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Solution for 3(2x-5)=x(x+1) equation: 



3(2x-5)=x(x+1)

We move all terms to the left:

3(2x-5)-(x(x+1))=0

We multiply parentheses

6x-(x(x+1))-15=0



We calculate terms in parentheses: -(x(x+1)), so:

x(x+1)

We multiply parentheses

x^2+x

Back to the equation:

-(x^2+x)



We get rid of parentheses

-x^2+6x-x-15=0

We add all the numbers together, and all the variables

-1x^2+5x-15=0

a = -1; b = 5; c = -15;
Δ = b2-4ac
Δ = 52-4·(-1)·(-15)
Δ = -35
Delta is less than zero, so there is no solution for the equation

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