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3(2x-6)+2x=x-2(3x-4)
We move all terms to the left:
3(2x-6)+2x-(x-2(3x-4))=0
We add all the numbers together, and all the variables
2x+3(2x-6)-(x-2(3x-4))=0
We multiply parentheses
2x+6x-(x-2(3x-4))-18=0
We calculate terms in parentheses: -(x-2(3x-4)), so:We add all the numbers together, and all the variables
x-2(3x-4)
We multiply parentheses
x-6x+8
We add all the numbers together, and all the variables
-5x+8
Back to the equation:
-(-5x+8)
8x-(-5x+8)-18=0
We get rid of parentheses
8x+5x-8-18=0
We add all the numbers together, and all the variables
13x-26=0
We move all terms containing x to the left, all other terms to the right
13x=26
x=26/13
x=2
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