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3(2x-6)+9=2(2x-3)+4x-23
We move all terms to the left:
3(2x-6)+9-(2(2x-3)+4x-23)=0
We multiply parentheses
6x-(2(2x-3)+4x-23)-18+9=0
We calculate terms in parentheses: -(2(2x-3)+4x-23), so:We add all the numbers together, and all the variables
2(2x-3)+4x-23
We add all the numbers together, and all the variables
4x+2(2x-3)-23
We multiply parentheses
4x+4x-6-23
We add all the numbers together, and all the variables
8x-29
Back to the equation:
-(8x-29)
6x-(8x-29)-9=0
We get rid of parentheses
6x-8x+29-9=0
We add all the numbers together, and all the variables
-2x+20=0
We move all terms containing x to the left, all other terms to the right
-2x=-20
x=-20/-2
x=+10
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