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3(2x-6)-2=3(x-2)+1
We move all terms to the left:
3(2x-6)-2-(3(x-2)+1)=0
We multiply parentheses
6x-(3(x-2)+1)-18-2=0
We calculate terms in parentheses: -(3(x-2)+1), so:We add all the numbers together, and all the variables
3(x-2)+1
We multiply parentheses
3x-6+1
We add all the numbers together, and all the variables
3x-5
Back to the equation:
-(3x-5)
6x-(3x-5)-20=0
We get rid of parentheses
6x-3x+5-20=0
We add all the numbers together, and all the variables
3x-15=0
We move all terms containing x to the left, all other terms to the right
3x=15
x=15/3
x=5
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