3(2x-6)-4=3(x-3)+5

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Solution for 3(2x-6)-4=3(x-3)+5 equation: 



3(2x-6)-4=3(x-3)+5

We move all terms to the left:

3(2x-6)-4-(3(x-3)+5)=0

We multiply parentheses

6x-(3(x-3)+5)-18-4=0



We calculate terms in parentheses: -(3(x-3)+5), so:

3(x-3)+5

We multiply parentheses

3x-9+5

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

6x-(3x-4)-22=0

We get rid of parentheses

6x-3x+4-22=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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