3(2x-6)-4=3(x-5)+20

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Solution for 3(2x-6)-4=3(x-5)+20 equation: 



3(2x-6)-4=3(x-5)+20

We move all terms to the left:

3(2x-6)-4-(3(x-5)+20)=0

We multiply parentheses

6x-(3(x-5)+20)-18-4=0



We calculate terms in parentheses: -(3(x-5)+20), so:

3(x-5)+20

We multiply parentheses

3x-15+20

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

6x-(3x+5)-22=0

We get rid of parentheses

6x-3x-5-22=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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