3(2x-6)=(-2x)+(-2)

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Solution for 3(2x-6)=(-2x)+(-2) equation: 



3(2x-6)=(-2x)+(-2)

We move all terms to the left:

3(2x-6)-((-2x)+(-2))=0

We multiply parentheses

6x-((-2x)+(-2))-18=0



We calculate terms in parentheses: -((-2x)+(-2)), so:

(-2x)+(-2)

We add all the numbers together, and all the variables

(-2x)-2

We get rid of parentheses

-2x-2

Back to the equation:

-(-2x-2)



We get rid of parentheses

6x+2x+2-18=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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