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3(2x-7)+1=2(x-5)
We move all terms to the left:
3(2x-7)+1-(2(x-5))=0
We multiply parentheses
6x-(2(x-5))-21+1=0
We calculate terms in parentheses: -(2(x-5)), so:We add all the numbers together, and all the variables
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
6x-(2x-10)-20=0
We get rid of parentheses
6x-2x+10-20=0
We add all the numbers together, and all the variables
4x-10=0
We move all terms containing x to the left, all other terms to the right
4x=10
x=10/4
x=2+1/2
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