3(2x-7)-10=9-2(5x+4)

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Solution for 3(2x-7)-10=9-2(5x+4) equation: 



3(2x-7)-10=9-2(5x+4)

We move all terms to the left:

3(2x-7)-10-(9-2(5x+4))=0

We multiply parentheses

6x-(9-2(5x+4))-21-10=0



We calculate terms in parentheses: -(9-2(5x+4)), so:

9-2(5x+4)

determiningTheFunctionDomain
-2(5x+4)+9

We multiply parentheses

-10x-8+9

We add all the numbers together, and all the variables

-10x+1

Back to the equation:

-(-10x+1)



We add all the numbers together, and all the variables

6x-(-10x+1)-31=0

We get rid of parentheses

6x+10x-1-31=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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