3(2x-7)=2(x+1.5)

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Solution for 3(2x-7)=2(x+1.5) equation: 



3(2x-7)=2(x+1.5)

We move all terms to the left:

3(2x-7)-(2(x+1.5))=0

We multiply parentheses

6x-(2(x+1.5))-21=0



We calculate terms in parentheses: -(2(x+1.5)), so:

2(x+1.5)

We multiply parentheses

2x+3

Back to the equation:

-(2x+3)



We get rid of parentheses

6x-2x-3-21=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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