3(2x-8)+10x=16

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Solution for 3(2x-8)+10x=16 equation: 



3(2x-8)+10x=16

We move all terms to the left:

3(2x-8)+10x-(16)=0

We add all the numbers together, and all the variables

10x+3(2x-8)-16=0

We multiply parentheses

10x+6x-24-16=0

We add all the numbers together, and all the variables

16x-40=0

We move all terms containing x to the left, all other terms to the right

16x=40

x=40/16

x=2+1/2

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